std::ratio_detail::is_ratio< T > Class Template Reference

A type trait to check if a type is a specialization of std::ratio as required in [ratio.general]. More...

Inheritance diagram for std::ratio_detail::is_ratio< T >:

Additional Inherited Members
Public Types inherited from std::integral_constant< bool, Value >< false >
using	type
	The type of this class.
using	type
	The type of this class.
using	value_type
	The type of the value.
using	value_type
	The type of the value.
Public Member Functions inherited from std::integral_constant< bool, Value >< false >
constexpr	operator value_type () const noexcept
	Implicit conversion to Type.
constexpr	operator value_type () const noexcept
	Implicit conversion to Type.
constexpr	operator value_type () const noexcept
	Implicit conversion to Type.
constexpr	operator value_type () const noexcept
	Implicit conversion to Type.
constexpr auto	operator() () const noexcept -> value_type
	Nullary function call operator.
constexpr auto	operator() () const noexcept -> value_type
	Nullary function call operator.
constexpr auto	operator() () const noexcept -> value_type
	Nullary function call operator.
constexpr auto	operator() () const noexcept -> value_type
	Nullary function call operator.
Static Public Attributes inherited from std::integral_constant< bool, Value >< false >
static constexpr value_type	value
	The constant.
static constexpr value_type	value
	The constant.
static constexpr value_type	value
	The constant.
static constexpr value_type	value
	The constant.

Detailed Description

template<typename T>
class std::ratio_detail::is_ratio< T >

A type trait to check if a type is a specialization of std::ratio as required in [ratio.general].

Template Parameters

T	The type to check; std::false_type if this is not a std::ratio specialization

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The documentation for this class was generated from the following file:

• stdlib/include/stdlib_detail/ratio.hpp